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10222014433 is a prime number
BaseRepresentation
bin10011000010100011…
…11000111111100001
3222101101112010200011
421201101320333201
5131413313430213
64410153124521
7511211455231
oct114121707741
928341463604
1010222014433
114376073814
121b933b9741
13c6b9b1a67
146cd835cc1
153ec61503d
hex261478fe1

10222014433 has 2 divisors, whose sum is σ = 10222014434. Its totient is φ = 10222014432.

The previous prime is 10222014403. The next prime is 10222014437. The reversal of 10222014433 is 33441022201.

10222014433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10214740624 + 7273809 = 101068^2 + 2697^2 .

It is a cyclic number.

It is not a de Polignac number, because 10222014433 - 213 = 10222006241 is a prime.

It is a super-2 number, since 2×102220144332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10222014437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111007216 + 5111007217.

It is an arithmetic number, because the mean of its divisors is an integer number (5111007217).

Almost surely, 210222014433 is an apocalyptic number.

It is an amenable number.

10222014433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10222014433 is an equidigital number, since it uses as much as digits as its factorization.

10222014433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 10222014433 its reverse (33441022201), we get a palindrome (43663036634).

The spelling of 10222014433 in words is "ten billion, two hundred twenty-two million, fourteen thousand, four hundred thirty-three".