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102230121113 is a prime number
BaseRepresentation
bin101111100110101100…
…0111101101010011001
3100202212121000020021222
41133031120331222121
53133331402333423
6114544110141425
710246233456221
oct1371530755231
9322777006258
10102230121113
113a3a02690aa
12179907b1875
139842859233
144d3b2dd081
1529d4e063c8
hex17cd63da99

102230121113 has 2 divisors, whose sum is σ = 102230121114. Its totient is φ = 102230121112.

The previous prime is 102230121109. The next prime is 102230121137. The reversal of 102230121113 is 311121032201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102152469769 + 77651344 = 319613^2 + 8812^2 .

It is a cyclic number.

It is not a de Polignac number, because 102230121113 - 22 = 102230121109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102230121091 and 102230121100.

It is not a weakly prime, because it can be changed into another prime (102230121143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51115060556 + 51115060557.

It is an arithmetic number, because the mean of its divisors is an integer number (51115060557).

Almost surely, 2102230121113 is an apocalyptic number.

It is an amenable number.

102230121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102230121113 is an equidigital number, since it uses as much as digits as its factorization.

102230121113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 102230121113 its reverse (311121032201), we get a palindrome (413351153314).

The spelling of 102230121113 in words is "one hundred two billion, two hundred thirty million, one hundred twenty-one thousand, one hundred thirteen".