1022311343541 has 4 divisors (see below), whose sum is σ = 1363081791392. Its totient is φ = 681540895692.

The previous prime is 1022311343527. The next prime is 1022311343567. The reversal of 1022311343541 is 1453431132201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1022311343541 - 2¹⁵ = 1022311310773 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1022311343499 and 1022311343508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1022311343441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170385223921 + ... + 170385223926.

It is an arithmetic number, because the mean of its divisors is an integer number (340770447848).

Almost surely, 2^{1022311343541} is an apocalyptic number.

It is an amenable number.

1022311343541 is a deficient number, since it is larger than the sum of its proper divisors (340770447851).

1022311343541 is an equidigital number, since it uses as much as digits as its factorization.

1022311343541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340770447850.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1022311343541 its reverse (1453431132201), we get a palindrome (2475742475742).

The spelling of 1022311343541 in words is "one trillion, twenty-two billion, three hundred eleven million, three hundred forty-three thousand, five hundred forty-one".