Search a number
-
+
102231310100131 is a prime number
BaseRepresentation
bin10111001111101010010100…
…111011000110011010100011
3111101222012212202220221122101
4113033222110323012122203
5101344424210341201011
61001232225425551231
730350653111101142
oct2717522473063243
9441865782827571
10102231310100131
112a635067428873
12b571142aa5517
1345074a9624844
141b36043bbb759
15bc440e8832c1
hex5cfa94ec66a3

102231310100131 has 2 divisors, whose sum is σ = 102231310100132. Its totient is φ = 102231310100130.

The previous prime is 102231310100063. The next prime is 102231310100159. The reversal of 102231310100131 is 131001013132201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102231310100131 - 221 = 102231308002979 is a prime.

It is a super-3 number, since 3×1022313101001313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 102231310100099 and 102231310100108.

It is not a weakly prime, because it can be changed into another prime (102231310700131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51115655050065 + 51115655050066.

It is an arithmetic number, because the mean of its divisors is an integer number (51115655050066).

Almost surely, 2102231310100131 is an apocalyptic number.

102231310100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

102231310100131 is an equidigital number, since it uses as much as digits as its factorization.

102231310100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 102231310100131 its reverse (131001013132201), we get a palindrome (233232323232332).

The spelling of 102231310100131 in words is "one hundred two trillion, two hundred thirty-one billion, three hundred ten million, one hundred thousand, one hundred thirty-one".