Base | Representation |
---|---|
bin | 1001010011000100110000… |
… | …1011010100011110001011 |
3 | 1100012100010100221202100102 |
4 | 2110301030023110132023 |
5 | 2314444304322402311 |
6 | 33424304055200015 |
7 | 2103415623623441 |
oct | 224611413243613 |
9 | 40170110852312 |
10 | 10223300200331 |
11 | 329174a495629 |
12 | 119141667600b |
13 | 59208c7a488a |
14 | 274b4b924b91 |
15 | 12ade8c2543b |
hex | 94c4c2d478b |
10223300200331 has 2 divisors, whose sum is σ = 10223300200332. Its totient is φ = 10223300200330.
The previous prime is 10223300200301. The next prime is 10223300200339. The reversal of 10223300200331 is 13300200332201.
It is a strong prime.
It is an emirp because it is prime and its reverse (13300200332201) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10223300200331 is a prime.
It is a super-4 number, since 4×102233002003314 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (10223300200339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111650100165 + 5111650100166.
It is an arithmetic number, because the mean of its divisors is an integer number (5111650100166).
Almost surely, 210223300200331 is an apocalyptic number.
10223300200331 is a deficient number, since it is larger than the sum of its proper divisors (1).
10223300200331 is an equidigital number, since it uses as much as digits as its factorization.
10223300200331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 10223300200331 its reverse (13300200332201), we get a palindrome (23523500532532).
The spelling of 10223300200331 in words is "ten trillion, two hundred twenty-three billion, three hundred million, two hundred thousand, three hundred thirty-one".
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