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10230222113 is a prime number
BaseRepresentation
bin10011000011100010…
…01100110100100001
3222101221222010111022
421201301030310201
5131422414101423
64411045055225
7511341311306
oct114161146441
928357863438
1010230222113
11437a76a321
121b960b7515
13c705c6887
146d09710ad
153ed1d6dc8
hex261c4cd21

10230222113 has 2 divisors, whose sum is σ = 10230222114. Its totient is φ = 10230222112.

The previous prime is 10230222089. The next prime is 10230222139. The reversal of 10230222113 is 31122203201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8334229264 + 1895992849 = 91292^2 + 43543^2 .

It is an emirp because it is prime and its reverse (31122203201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10230222113 - 212 = 10230218017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10230222091 and 10230222100.

It is not a weakly prime, because it can be changed into another prime (10230222173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115111056 + 5115111057.

It is an arithmetic number, because the mean of its divisors is an integer number (5115111057).

Almost surely, 210230222113 is an apocalyptic number.

It is an amenable number.

10230222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10230222113 is an equidigital number, since it uses as much as digits as its factorization.

10230222113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10230222113 its reverse (31122203201), we get a palindrome (41352425314).

The spelling of 10230222113 in words is "ten billion, two hundred thirty million, two hundred twenty-two thousand, one hundred thirteen".