Base | Representation |
---|---|
bin | 1001010011100001110111… |
… | …0110111001111001001001 |
3 | 1100020002021212011200112012 |
4 | 2110320131312321321021 |
5 | 2320111304413444431 |
6 | 33432035231225305 |
7 | 2104113342606224 |
oct | 224703566717111 |
9 | 40202255150465 |
10 | 10231113031241 |
11 | 3294a99644083 |
12 | 1192a37078235 |
13 | 592a3630394b |
14 | 27528d3ca5bb |
15 | 12b204a9d22b |
hex | 94e1ddb9e49 |
10231113031241 has 2 divisors, whose sum is σ = 10231113031242. Its totient is φ = 10231113031240.
The previous prime is 10231113031187. The next prime is 10231113031297. The reversal of 10231113031241 is 14213031113201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7668219414025 + 2562893617216 = 2769155^2 + 1600904^2 .
It is a cyclic number.
It is not a de Polignac number, because 10231113031241 - 222 = 10231108836937 is a prime.
It is not a weakly prime, because it can be changed into another prime (10231113031141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115556515620 + 5115556515621.
It is an arithmetic number, because the mean of its divisors is an integer number (5115556515621).
Almost surely, 210231113031241 is an apocalyptic number.
It is an amenable number.
10231113031241 is a deficient number, since it is larger than the sum of its proper divisors (1).
10231113031241 is an equidigital number, since it uses as much as digits as its factorization.
10231113031241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 10231113031241 its reverse (14213031113201), we get a palindrome (24444144144442).
The spelling of 10231113031241 in words is "ten trillion, two hundred thirty-one billion, one hundred thirteen million, thirty-one thousand, two hundred forty-one".
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