Base | Representation |
---|---|
bin | 1001010011100010101011… |
… | …1110011110110001011001 |
3 | 1100020002212012022102001221 |
4 | 2110320222332132301121 |
5 | 2320112232234333423 |
6 | 33432113132412041 |
7 | 2104121654415526 |
oct | 224705276366131 |
9 | 40202765272057 |
10 | 10231333121113 |
11 | 32950a18a8935 |
12 | 1192a98917021 |
13 | 592a6caa3240 |
14 | 2752b071c14d |
15 | 12b219074e5d |
hex | 94e2af9ec59 |
10231333121113 has 16 divisors (see below), whose sum is σ = 11106885113856. Its totient is φ = 9368451429120.
The previous prime is 10231333121099. The next prime is 10231333121129. The reversal of 10231333121113 is 31112133313201.
It is a cyclic number.
It is not a de Polignac number, because 10231333121113 - 217 = 10231332990041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10231333121173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9949233 + ... + 10929313.
It is an arithmetic number, because the mean of its divisors is an integer number (694180319616).
Almost surely, 210231333121113 is an apocalyptic number.
10231333121113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10231333121113 is a deficient number, since it is larger than the sum of its proper divisors (875551992743).
10231333121113 is a wasteful number, since it uses less digits than its factorization.
10231333121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 986544.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 10231333121113 its reverse (31112133313201), we get a palindrome (41343466434314).
The spelling of 10231333121113 in words is "ten trillion, two hundred thirty-one billion, three hundred thirty-three million, one hundred twenty-one thousand, one hundred thirteen".
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