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102313413007 = 137870262539
BaseRepresentation
bin101111101001001011…
…0101100100110001111
3100210002101201220021221
41133102112230212033
53134014213204012
6115000243304211
710251264442561
oct1372226544617
9323071656257
10102313413007
113a433288583
12179b467b067
139856b9ca90
144d483c1331
1529dc3aa507
hex17d25ac98f

102313413007 has 4 divisors (see below), whose sum is σ = 110183675560. Its totient is φ = 94443150456.

The previous prime is 102313413001. The next prime is 102313413011. The reversal of 102313413007 is 700314313201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102313413007 is a prime.

It is a super-2 number, since 2×1023134130072 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102313413001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3935131257 + ... + 3935131282.

It is an arithmetic number, because the mean of its divisors is an integer number (27545918890).

Almost surely, 2102313413007 is an apocalyptic number.

102313413007 is a deficient number, since it is larger than the sum of its proper divisors (7870262553).

102313413007 is an equidigital number, since it uses as much as digits as its factorization.

102313413007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7870262552.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 102313413007 its reverse (700314313201), we get a palindrome (802627726208).

The spelling of 102313413007 in words is "one hundred two billion, three hundred thirteen million, four hundred thirteen thousand, seven".

Divisors: 1 13 7870262539 102313413007