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102315113 is a prime number
BaseRepresentation
bin1100001100100…
…11010001101001
321010112010221122
412012103101221
5202143040423
614052545025
72351443535
oct606232151
9233463848
10102315113
115283294a
122a322175
13182744b4
14d834bc5
158eb08c8
hex6193469

102315113 has 2 divisors, whose sum is σ = 102315114. Its totient is φ = 102315112.

The previous prime is 102315091. The next prime is 102315119. The reversal of 102315113 is 311513201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97871449 + 4443664 = 9893^2 + 2108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102315113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102315091 and 102315100.

It is not a weakly prime, because it can be changed into another prime (102315119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51157556 + 51157557.

It is an arithmetic number, because the mean of its divisors is an integer number (51157557).

Almost surely, 2102315113 is an apocalyptic number.

It is an amenable number.

102315113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102315113 is an equidigital number, since it uses as much as digits as its factorization.

102315113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 102315113 is about 10115.0933263119. The cubic root of 102315113 is about 467.7135257639.

Adding to 102315113 its reverse (311513201), we get a palindrome (413828314).

The spelling of 102315113 in words is "one hundred two million, three hundred fifteen thousand, one hundred thirteen".