Base | Representation |
---|---|
bin | 10011000011101100… |
… | …01010101100100011 |
3 | 222102001102021112012 |
4 | 21201312022230203 |
5 | 131423232233011 |
6 | 4411133023135 |
7 | 511355343263 |
oct | 114166125443 |
9 | 28361367465 |
10 | 10231524131 |
11 | 4380479574 |
12 | 1b96624aab |
13 | c709613ba |
14 | 6d0bcd7a3 |
15 | 3ed392a8b |
hex | 261d8ab23 |
10231524131 has 2 divisors, whose sum is σ = 10231524132. Its totient is φ = 10231524130.
The previous prime is 10231524091. The next prime is 10231524139. The reversal of 10231524131 is 13142513201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10231524131 is a prime.
It is a super-2 number, since 2×102315241312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10231524097 and 10231524106.
It is not a weakly prime, because it can be changed into another prime (10231524139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115762065 + 5115762066.
It is an arithmetic number, because the mean of its divisors is an integer number (5115762066).
Almost surely, 210231524131 is an apocalyptic number.
10231524131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10231524131 is an equidigital number, since it uses as much as digits as its factorization.
10231524131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
The spelling of 10231524131 in words is "ten billion, two hundred thirty-one million, five hundred twenty-four thousand, one hundred thirty-one".
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