Base | Representation |
---|---|
bin | 101111101001011010… |
… | …0110101010011101001 |
3 | 100210002221121021001022 |
4 | 1133102310311103221 |
5 | 3134023224004001 |
6 | 115001124502225 |
7 | 10251421544615 |
oct | 1372264652351 |
9 | 323087537038 |
10 | 102321313001 |
11 | 3a4377939a6 |
12 | 179b724a975 |
13 | 985870782b |
14 | 4d4947a345 |
15 | 29dce1b11b |
hex | 17d2d354e9 |
102321313001 has 2 divisors, whose sum is σ = 102321313002. Its totient is φ = 102321313000.
The previous prime is 102321312979. The next prime is 102321313019. The reversal of 102321313001 is 100313123201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65817389401 + 36503923600 = 256549^2 + 191060^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102321313001 is a prime.
It is a super-2 number, since 2×1023213130012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (102321313051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51160656500 + 51160656501.
It is an arithmetic number, because the mean of its divisors is an integer number (51160656501).
Almost surely, 2102321313001 is an apocalyptic number.
It is an amenable number.
102321313001 is a deficient number, since it is larger than the sum of its proper divisors (1).
102321313001 is an equidigital number, since it uses as much as digits as its factorization.
102321313001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 102321313001 its reverse (100313123201), we get a palindrome (202634436202).
The spelling of 102321313001 in words is "one hundred two billion, three hundred twenty-one million, three hundred thirteen thousand, one".
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