Base | Representation |
---|---|
bin | 10111010001001000001110… |
… | …100000101001000000110011 |
3 | 111102022212010101022112102220 |
4 | 113101020032200221000303 |
5 | 101403102202330411430 |
6 | 1001350422233012123 |
7 | 30361152453061614 |
oct | 2721101640510063 |
9 | 442285111275386 |
10 | 102332134232115 |
11 | 2a6738a5a87487 |
12 | b5887a0854043 |
13 | 4513b56ab6238 |
14 | 1b3ac8a489c0b |
15 | bc6d61110110 |
hex | 5d120e829033 |
102332134232115 has 32 divisors (see below), whose sum is σ = 167565926223360. Its totient is φ = 53313744312576.
The previous prime is 102332134232087. The next prime is 102332134232161. The reversal of 102332134232115 is 511232431233201.
It is a happy number.
It is not a de Polignac number, because 102332134232115 - 213 = 102332134223923 is a prime.
It is a super-3 number, since 3×1023321342321153 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 461655967 + ... + 461877576.
It is an arithmetic number, because the mean of its divisors is an integer number (5236435194480).
Almost surely, 2102332134232115 is an apocalyptic number.
102332134232115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
102332134232115 is a deficient number, since it is larger than the sum of its proper divisors (65233791991245).
102332134232115 is an equidigital number, since it uses as much as digits as its factorization.
102332134232115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 923533723.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 102332134232115 its reverse (511232431233201), we get a palindrome (613564565465316).
The spelling of 102332134232115 in words is "one hundred two trillion, three hundred thirty-two billion, one hundred thirty-four million, two hundred thirty-two thousand, one hundred fifteen".
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