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10233354121113 = 33411118040371
BaseRepresentation
bin1001010011101010001101…
…1011111110111110011001
31100020022002001011211212210
42110322203123332332121
52320130402123333423
633433045445425333
72104223024553024
oct224724333767631
940208061154783
1010233354121113
113295a39689072
12119336170b249
135930026c0c26
14275422cc21bb
1512b2d66d4b93
hex94ea36fef99

10233354121113 has 4 divisors (see below), whose sum is σ = 13644472161488. Its totient is φ = 6822236080740.

The previous prime is 10233354121087. The next prime is 10233354121181. The reversal of 10233354121113 is 31112145333201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10233354121113 - 26 = 10233354121049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10233354121183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1705559020183 + ... + 1705559020188.

It is an arithmetic number, because the mean of its divisors is an integer number (3411118040372).

Almost surely, 210233354121113 is an apocalyptic number.

It is an amenable number.

10233354121113 is a deficient number, since it is larger than the sum of its proper divisors (3411118040375).

10233354121113 is an equidigital number, since it uses as much as digits as its factorization.

10233354121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3411118040374.

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 10233354121113 its reverse (31112145333201), we get a palindrome (41345499454314).

The spelling of 10233354121113 in words is "ten trillion, two hundred thirty-three billion, three hundred fifty-four million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 3411118040371 10233354121113