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10234141223 = 12178409319
BaseRepresentation
bin10011000100000000…
…01001101000100111
3222102020100020111112
421202000021220213
5131424420004343
64411305055235
7511416523265
oct114200115047
928366306445
1010234141223
1143819a6859
121b9748751b
13c71369687
146d12b1435
153ed70d218
hex262009a27

10234141223 has 4 divisors (see below), whose sum is σ = 10242551760. Its totient is φ = 10225730688.

The previous prime is 10234141213. The next prime is 10234141237. The reversal of 10234141223 is 32214143201.

10234141223 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10234141223 - 28 = 10234140967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10234141213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4203443 + ... + 4205876.

It is an arithmetic number, because the mean of its divisors is an integer number (2560637940).

Almost surely, 210234141223 is an apocalyptic number.

10234141223 is a deficient number, since it is larger than the sum of its proper divisors (8410537).

10234141223 is an equidigital number, since it uses as much as digits as its factorization.

10234141223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8410536.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10234141223 its reverse (32214143201), we get a palindrome (42448284424).

The spelling of 10234141223 in words is "ten billion, two hundred thirty-four million, one hundred forty-one thousand, two hundred twenty-three".

Divisors: 1 1217 8409319 10234141223