Base | Representation |
---|---|
bin | 11101111000011110100001… |
… | …110111101000000111110111 |
3 | 122020100001101210112211120222 |
4 | 131320132201313220013313 |
5 | 114211224203010114333 |
6 | 1143303313422044555 |
7 | 36453046434031454 |
oct | 3570364167500767 |
9 | 566301353484528 |
10 | 131424420004343 |
11 | 3896a868957194 |
12 | 128a6b2441975b |
13 | 58443674b206b |
14 | 2464d93ad482b |
15 | 102d9b6510298 |
hex | 7787a1de81f7 |
131424420004343 has 2 divisors, whose sum is σ = 131424420004344. Its totient is φ = 131424420004342.
The previous prime is 131424420004307. The next prime is 131424420004351. The reversal of 131424420004343 is 343400024424131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131424420004343 - 216 = 131424419938807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131424420004303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712210002171 + 65712210002172.
It is an arithmetic number, because the mean of its divisors is an integer number (65712210002172).
Almost surely, 2131424420004343 is an apocalyptic number.
131424420004343 is a deficient number, since it is larger than the sum of its proper divisors (1).
131424420004343 is an equidigital number, since it uses as much as digits as its factorization.
131424420004343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 131424420004343 its reverse (343400024424131), we get a palindrome (474824444428474).
The spelling of 131424420004343 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, four hundred twenty million, four thousand, three hundred forty-three".
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