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10240201200433 is a prime number
BaseRepresentation
bin1001010100000011101110…
…0011100001001100110001
31100020221202020011111221011
42111000323203201030301
52320233413001403213
633440141122230521
72104554506016301
oct225007343411461
940227666144834
1010240201200433
113298932686106
1211947527b5441
13593854114759
142758b23d3601
1512b58789403d
hex9503b8e1331

10240201200433 has 2 divisors, whose sum is σ = 10240201200434. Its totient is φ = 10240201200432.

The previous prime is 10240201200419. The next prime is 10240201200457. The reversal of 10240201200433 is 33400210204201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10103898467569 + 136302732864 = 3178663^2 + 369192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10240201200433 is a prime.

It is not a weakly prime, because it can be changed into another prime (10240201200413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5120100600216 + 5120100600217.

It is an arithmetic number, because the mean of its divisors is an integer number (5120100600217).

Almost surely, 210240201200433 is an apocalyptic number.

It is an amenable number.

10240201200433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10240201200433 is an equidigital number, since it uses as much as digits as its factorization.

10240201200433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 10240201200433 its reverse (33400210204201), we get a palindrome (43640411404634).

The spelling of 10240201200433 in words is "ten trillion, two hundred forty billion, two hundred one million, two hundred thousand, four hundred thirty-three".