Base | Representation |
---|---|
bin | 10111010010100110010001… |
… | …110010100101111101110111 |
3 | 111102200111210022201221120202 |
4 | 113102212101302211331313 |
5 | 101411231012434020320 |
6 | 1001505043125551115 |
7 | 30401356141334405 |
oct | 2722462162457567 |
9 | 442614708657522 |
10 | 102433121001335 |
11 | 2a702708419933 |
12 | b5a4284b7549b |
13 | 452052bb7c897 |
14 | 1b41b0a5b2475 |
15 | bc97c1cb5b75 |
hex | 5d2991ca5f77 |
102433121001335 has 16 divisors (see below), whose sum is σ = 123745643481600. Its totient is φ = 81396260564736.
The previous prime is 102433121001331. The next prime is 102433121001383. The reversal of 102433121001335 is 533100121334201.
It is a cyclic number.
It is not a de Polignac number, because 102433121001335 - 22 = 102433121001331 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102433121001298 and 102433121001307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102433121001331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20402030 + ... + 24922059.
It is an arithmetic number, because the mean of its divisors is an integer number (7734102717600).
Almost surely, 2102433121001335 is an apocalyptic number.
102433121001335 is a deficient number, since it is larger than the sum of its proper divisors (21312522480265).
102433121001335 is a wasteful number, since it uses less digits than its factorization.
102433121001335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45327130.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 102433121001335 its reverse (533100121334201), we get a palindrome (635533242335536).
The spelling of 102433121001335 in words is "one hundred two trillion, four hundred thirty-three billion, one hundred twenty-one million, one thousand, three hundred thirty-five".
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