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10243352131 = 29353219039
BaseRepresentation
bin10011000101000110…
…10010011001000011
3222102212200012111021
421202203102121003
5131434244232011
64412234330311
7511561025245
oct114243223103
928385605437
1010243352131
114387118081
121b9a589997
13c7324300c
146d25cc095
153ee42c471
hex2628d2643

10243352131 has 4 divisors (see below), whose sum is σ = 10596571200. Its totient is φ = 9890133064.

The previous prime is 10243352129. The next prime is 10243352167. The reversal of 10243352131 is 13125334201.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10243352131 - 21 = 10243352129 is a prime.

It is a super-2 number, since 2×102433521312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10243352096 and 10243352105.

It is not an unprimeable number, because it can be changed into a prime (10223352131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176609491 + ... + 176609548.

It is an arithmetic number, because the mean of its divisors is an integer number (2649142800).

Almost surely, 210243352131 is an apocalyptic number.

10243352131 is a deficient number, since it is larger than the sum of its proper divisors (353219069).

10243352131 is an equidigital number, since it uses as much as digits as its factorization.

10243352131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 353219068.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 10243352131 its reverse (13125334201), we get a palindrome (23368686332).

The spelling of 10243352131 in words is "ten billion, two hundred forty-three million, three hundred fifty-two thousand, one hundred thirty-one".

Divisors: 1 29 353219039 10243352131