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1024423253153 is a prime number
BaseRepresentation
bin11101110100001000110…
…00100101010010100001
310121221012211002020100122
432322010120211102201
5113241004323100103
62102340305330025
7134004106656506
oct16720430452241
93557184066318
101024423253153
11365501246533
12146659336915
13757ab188521
1437821d7b4ad
151b9aa9b0b38
hexee846254a1

1024423253153 has 2 divisors, whose sum is σ = 1024423253154. Its totient is φ = 1024423253152.

The previous prime is 1024423253111. The next prime is 1024423253173. The reversal of 1024423253153 is 3513523244201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 759602888704 + 264820364449 = 871552^2 + 514607^2 .

It is an emirp because it is prime and its reverse (3513523244201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1024423253153 - 214 = 1024423236769 is a prime.

It is not a weakly prime, because it can be changed into another prime (1024423253173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 512211626576 + 512211626577.

It is an arithmetic number, because the mean of its divisors is an integer number (512211626577).

Almost surely, 21024423253153 is an apocalyptic number.

It is an amenable number.

1024423253153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1024423253153 is an equidigital number, since it uses as much as digits as its factorization.

1024423253153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 1024423253153 its reverse (3513523244201), we get a palindrome (4537946497354).

The spelling of 1024423253153 in words is "one trillion, twenty-four billion, four hundred twenty-three million, two hundred fifty-three thousand, one hundred fifty-three".