Search a number
-
+
10244475042433 is a prime number
BaseRepresentation
bin1001010100010011101001…
…0010111011101010000001
31100021100210002011011222121
42111010322102323222001
52320321141102324213
633442125153404241
72105065433045122
oct225047222735201
940240702134877
1010244475042433
11329a7260a7935
121195545b69681
135940856a5948
14275b99c6c049
1512b737bac88d
hex9513a4bba81

10244475042433 has 2 divisors, whose sum is σ = 10244475042434. Its totient is φ = 10244475042432.

The previous prime is 10244475042341. The next prime is 10244475042457. The reversal of 10244475042433 is 33424057444201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6924729094144 + 3319745948289 = 2631488^2 + 1822017^2 .

It is an emirp because it is prime and its reverse (33424057444201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10244475042433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10244475042433.

It is not a weakly prime, because it can be changed into another prime (10244475042733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5122237521216 + 5122237521217.

It is an arithmetic number, because the mean of its divisors is an integer number (5122237521217).

Almost surely, 210244475042433 is an apocalyptic number.

It is an amenable number.

10244475042433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10244475042433 is an equidigital number, since it uses as much as digits as its factorization.

10244475042433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1290240, while the sum is 43.

The spelling of 10244475042433 in words is "ten trillion, two hundred forty-four billion, four hundred seventy-five million, forty-two thousand, four hundred thirty-three".