Base | Representation |
---|---|
bin | 1001010100110000011011… |
… | …1100000100000011110011 |
3 | 1100022002201200022120212020 |
4 | 2111030012330010003303 |
5 | 2320433003024002430 |
6 | 33445444110002523 |
7 | 2105461104401655 |
oct | 225140674040363 |
9 | 40262650276766 |
10 | 10252203344115 |
11 | 32a2a31571317 |
12 | 1196b421a6443 |
13 | 594a17849c15 |
14 | 2762d040c6d5 |
15 | 12ba3b3d9b10 |
hex | 95306f040f3 |
10252203344115 has 32 divisors (see below), whose sum is σ = 16767455486976. Its totient is φ = 5346738946560.
The previous prime is 10252203344111. The next prime is 10252203344137. The reversal of 10252203344115 is 51144330225201.
It is not a de Polignac number, because 10252203344115 - 22 = 10252203344111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10252203344111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5682966 + ... + 7266395.
It is an arithmetic number, because the mean of its divisors is an integer number (523982983968).
Almost surely, 210252203344115 is an apocalyptic number.
10252203344115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10252203344115 is a deficient number, since it is larger than the sum of its proper divisors (6515252142861).
10252203344115 is a wasteful number, since it uses less digits than its factorization.
10252203344115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12950539.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 10252203344115 its reverse (51144330225201), we get a palindrome (61396533569316).
The spelling of 10252203344115 in words is "ten trillion, two hundred fifty-two billion, two hundred three million, three hundred forty-four thousand, one hundred fifteen".
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