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102531174611401 is a prime number
BaseRepresentation
bin10111010100000001100110…
…001111011011100111001001
3111110000212212211220102210101
4113110001212033123213021
5101414332321200031101
61002022101003045401
730411430042302604
oct2724014617334711
9443025784812711
10102531174611401
112a7402550a4408
12b5bb28ab10861
1345298573655b3
141b4676cd3133b
15bcc1101cc401
hex5d40663db9c9

102531174611401 has 2 divisors, whose sum is σ = 102531174611402. Its totient is φ = 102531174611400.

The previous prime is 102531174611381. The next prime is 102531174611407. The reversal of 102531174611401 is 104116471135201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102324331571401 + 206843040000 = 10115549^2 + 454800^2 .

It is a cyclic number.

It is not a de Polignac number, because 102531174611401 - 225 = 102531141056969 is a prime.

It is not a weakly prime, because it can be changed into another prime (102531174611407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51265587305700 + 51265587305701.

It is an arithmetic number, because the mean of its divisors is an integer number (51265587305701).

Almost surely, 2102531174611401 is an apocalyptic number.

It is an amenable number.

102531174611401 is a deficient number, since it is larger than the sum of its proper divisors (1).

102531174611401 is an equidigital number, since it uses as much as digits as its factorization.

102531174611401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 37.

The spelling of 102531174611401 in words is "one hundred two trillion, five hundred thirty-one billion, one hundred seventy-four million, six hundred eleven thousand, four hundred one".