Base | Representation |
---|---|
bin | 11101110101110100010… |
… | …01000000111000110011 |
3 | 10122000112200010220122210 |
4 | 32322322021000320303 |
5 | 113244331214012210 |
6 | 2103010004103203 |
7 | 134035340621661 |
oct | 16727211007063 |
9 | 3560480126583 |
10 | 1025325141555 |
11 | 365924348650 |
12 | 14686b394b03 |
13 | 758c2c935c0 |
14 | 378a9a69c31 |
15 | 1ba0ec61e20 |
hex | eeba240e33 |
1025325141555 has 32 divisors (see below), whose sum is σ = 1927324465920. Its totient is φ = 458886775680.
The previous prime is 1025325141493. The next prime is 1025325141569. The reversal of 1025325141555 is 5551415235201.
1025325141555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1025325141555 - 211 = 1025325139507 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 239001385 + ... + 239005674.
It is an arithmetic number, because the mean of its divisors is an integer number (60228889560).
Almost surely, 21025325141555 is an apocalyptic number.
1025325141555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1025325141555 is a deficient number, since it is larger than the sum of its proper divisors (901999324365).
1025325141555 is a wasteful number, since it uses less digits than its factorization.
1025325141555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 478007091.
The product of its (nonzero) digits is 150000, while the sum is 39.
The spelling of 1025325141555 in words is "one trillion, twenty-five billion, three hundred twenty-five million, one hundred forty-one thousand, five hundred fifty-five".
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