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10254834133 = 79129808027
BaseRepresentation
bin10011000110011110…
…00101100111010101
3222110200021112211121
421203033011213111
5132000214143013
64413324403541
7512060436415
oct114317054725
928420245747
1010254834133
11439264a735
121ba23a65b1
13c757332bb
146d3d3a645
1540044958d
hex2633c59d5

10254834133 has 4 divisors (see below), whose sum is σ = 10384642240. Its totient is φ = 10125026028.

The previous prime is 10254834127. The next prime is 10254834137. The reversal of 10254834133 is 33143845201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33143845201 = 171949637953.

It is a cyclic number.

It is not a de Polignac number, because 10254834133 - 213 = 10254825941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10254834137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64903935 + ... + 64904092.

It is an arithmetic number, because the mean of its divisors is an integer number (2596160560).

Almost surely, 210254834133 is an apocalyptic number.

It is an amenable number.

10254834133 is a deficient number, since it is larger than the sum of its proper divisors (129808107).

10254834133 is an equidigital number, since it uses as much as digits as its factorization.

10254834133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129808106.

The product of its (nonzero) digits is 34560, while the sum is 34.

The spelling of 10254834133 in words is "ten billion, two hundred fifty-four million, eight hundred thirty-four thousand, one hundred thirty-three".

Divisors: 1 79 129808027 10254834133