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10255433 is a prime number
BaseRepresentation
bin100111000111…
…110001001001
3201022000210212
4213013301021
510111133213
61003450505
7153112136
oct47076111
921260725
1010255433
115875071
123526a35
132180c06
14150d58d
15d789a8
hex9c7c49

10255433 has 2 divisors, whose sum is σ = 10255434. Its totient is φ = 10255432.

The previous prime is 10255429. The next prime is 10255481. The reversal of 10255433 is 33455201.

10255433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6538249 + 3717184 = 2557^2 + 1928^2 .

It is a cyclic number.

It is not a de Polignac number, because 10255433 - 22 = 10255429 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10255399 and 10255408.

It is not a weakly prime, because it can be changed into another prime (10255423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5127716 + 5127717.

It is an arithmetic number, because the mean of its divisors is an integer number (5127717).

Almost surely, 210255433 is an apocalyptic number.

It is an amenable number.

10255433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10255433 is an equidigital number, since it uses as much as digits as its factorization.

10255433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 10255433 is about 3202.4104983590. The cubic root of 10255433 is about 217.2624472946.

The spelling of 10255433 in words is "ten million, two hundred fifty-five thousand, four hundred thirty-three".