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102587113 is a prime number
BaseRepresentation
bin1100001110101…
…01101011101001
321011000222001201
412013111223221
5202230241423
614102444201
72353655536
oct607255351
9234028051
10102587113
11529a9242
122a433661
131833b245
14d8a5d8d
1590162ad
hex61d5ae9

102587113 has 2 divisors, whose sum is σ = 102587114. Its totient is φ = 102587112.

The previous prime is 102587083. The next prime is 102587131. The reversal of 102587113 is 311785201.

Together with next prime (102587131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80946009 + 21641104 = 8997^2 + 4652^2 .

It is a cyclic number.

It is not a de Polignac number, because 102587113 - 25 = 102587081 is a prime.

It is not a weakly prime, because it can be changed into another prime (102587183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51293556 + 51293557.

It is an arithmetic number, because the mean of its divisors is an integer number (51293557).

Almost surely, 2102587113 is an apocalyptic number.

It is an amenable number.

102587113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102587113 is an equidigital number, since it uses as much as digits as its factorization.

102587113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 28.

The square root of 102587113 is about 10128.5296563716. The cubic root of 102587113 is about 468.1276239586.

It can be divided in two parts, 10258 and 7113, that added together give a palindrome (17371).

The spelling of 102587113 in words is "one hundred two million, five hundred eighty-seven thousand, one hundred thirteen".