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102648433 is a prime number
BaseRepresentation
bin1100001111001…
…00101001110001
321011011002011211
412013210221301
5202234222213
614104040121
72354332366
oct607445161
9234132154
10102648433
1152a40318
122a463041
1318360124
14d8c046d
15902953d
hex61e4a71

102648433 has 2 divisors, whose sum is σ = 102648434. Its totient is φ = 102648432.

The previous prime is 102648419. The next prime is 102648437. The reversal of 102648433 is 334846201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67043344 + 35605089 = 8188^2 + 5967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102648433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102648395 and 102648404.

It is not a weakly prime, because it can be changed into another prime (102648437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51324216 + 51324217.

It is an arithmetic number, because the mean of its divisors is an integer number (51324217).

Almost surely, 2102648433 is an apocalyptic number.

It is an amenable number.

102648433 is a deficient number, since it is larger than the sum of its proper divisors (1).

102648433 is an equidigital number, since it uses as much as digits as its factorization.

102648433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

The square root of 102648433 is about 10131.5562970355. The cubic root of 102648433 is about 468.2208776091.

The spelling of 102648433 in words is "one hundred two million, six hundred forty-eight thousand, four hundred thirty-three".