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1030011824713 is a prime number
BaseRepresentation
bin11101111110100010111…
…11010010101001001001
310122110122021222002022111
432333101133102221021
5113333431011342323
62105103024022321
7134262440024164
oct16772137225111
93573567862274
101030011824713
11367909906013
12147758a619a1
137618bc40bc1
1437bd228cadb
151bbd6428c0d
hexefd17d2a49

1030011824713 has 2 divisors, whose sum is σ = 1030011824714. Its totient is φ = 1030011824712.

The previous prime is 1030011824657. The next prime is 1030011824761. The reversal of 1030011824713 is 3174281100301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1025980590649 + 4031234064 = 1012907^2 + 63492^2 .

It is an emirp because it is prime and its reverse (3174281100301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1030011824713 is a prime.

It is not a weakly prime, because it can be changed into another prime (1030011824213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515005912356 + 515005912357.

It is an arithmetic number, because the mean of its divisors is an integer number (515005912357).

Almost surely, 21030011824713 is an apocalyptic number.

It is an amenable number.

1030011824713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030011824713 is an equidigital number, since it uses as much as digits as its factorization.

1030011824713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

The spelling of 1030011824713 in words is "one trillion, thirty billion, eleven million, eight hundred twenty-four thousand, seven hundred thirteen".