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103010311147 is a prime number
BaseRepresentation
bin101111111101111100…
…1001001101111101011
3100211212222001222211011
41133323321021233223
53141431114424042
6115153340244351
710304456124562
oct1377371115753
9324788058734
10103010311147
113a7606a9457
1217b69b406b7
139938394343
144db2b8cbd9
152a2d668a17
hex17fbe49beb

103010311147 has 2 divisors, whose sum is σ = 103010311148. Its totient is φ = 103010311146.

The previous prime is 103010311031. The next prime is 103010311189. The reversal of 103010311147 is 741113010301.

It is a strong prime.

It is an emirp because it is prime and its reverse (741113010301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103010311147 is a prime.

It is a super-2 number, since 2×1030103111472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103010312147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505155573 + 51505155574.

It is an arithmetic number, because the mean of its divisors is an integer number (51505155574).

Almost surely, 2103010311147 is an apocalyptic number.

103010311147 is a deficient number, since it is larger than the sum of its proper divisors (1).

103010311147 is an equidigital number, since it uses as much as digits as its factorization.

103010311147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 103010311147 its reverse (741113010301), we get a palindrome (844123321448).

The spelling of 103010311147 in words is "one hundred three billion, ten million, three hundred eleven thousand, one hundred forty-seven".