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1030113232147 is a prime number
BaseRepresentation
bin11101111110101111000…
…10001000010100010011
310122110220100210010011101
432333113202020110103
5113334132441412042
62105121045325231
7134265111000526
oct16772742102423
93573810703141
101030113232147
11367961078a0a
12147786a06817
13761a6c581bc
1437c01928bbd
151bbe02aa6b7
hexefd7888513

1030113232147 has 2 divisors, whose sum is σ = 1030113232148. Its totient is φ = 1030113232146.

The previous prime is 1030113232133. The next prime is 1030113232177. The reversal of 1030113232147 is 7412323110301.

It is a weak prime.

It is an emirp because it is prime and its reverse (7412323110301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1030113232147 - 227 = 1029979014419 is a prime.

It is a super-2 number, since 2×10301132321472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1030113232177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515056616073 + 515056616074.

It is an arithmetic number, because the mean of its divisors is an integer number (515056616074).

Almost surely, 21030113232147 is an apocalyptic number.

1030113232147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030113232147 is an equidigital number, since it uses as much as digits as its factorization.

1030113232147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 1030113232147 its reverse (7412323110301), we get a palindrome (8442436342448).

The spelling of 1030113232147 in words is "one trillion, thirty billion, one hundred thirteen million, two hundred thirty-two thousand, one hundred forty-seven".