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103013003101102 = 251506501550551
BaseRepresentation
bin10111011011000010010101…
…011101010000001110101110
3111111201221120022012210002221
4113123002111131100032232
5102000231112243213402
61003031304215505554
730461305151011153
oct2733022535201656
9444657508183087
10103013003101102
112a9066297861a6
12b67873a3882ba
1345631138921c3
141b61bdaa4022a
15bd9910879337
hex5db0957503ae

103013003101102 has 4 divisors (see below), whose sum is σ = 154519504651656. Its totient is φ = 51506501550550.

The previous prime is 103013003101093. The next prime is 103013003101133. The reversal of 103013003101102 is 201101300310301.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1030130031011022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25753250775274 + ... + 25753250775277.

It is an arithmetic number, because the mean of its divisors is an integer number (38629876162914).

Almost surely, 2103013003101102 is an apocalyptic number.

103013003101102 is a deficient number, since it is larger than the sum of its proper divisors (51506501550554).

103013003101102 is an equidigital number, since it uses as much as digits as its factorization.

103013003101102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51506501550553.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103013003101102 its reverse (201101300310301), we get a palindrome (304114303411403).

The spelling of 103013003101102 in words is "one hundred three trillion, thirteen billion, three million, one hundred one thousand, one hundred two".

Divisors: 1 2 51506501550551 103013003101102