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1030221113130 = 23251123295329437
BaseRepresentation
bin11101111110111011111…
…01101010011100101010
310122111011212210001001100
432333131331222130222
5113334343101110010
62105135501502230
7134300560655406
oct16773575523452
93574155701040
101030221113130
11367a06a62550
121477b6b71976
13761c33cabc1
1437c11dac106
151bbe99ba2c0
hexefddf6a72a

1030221113130 has 384 divisors, whose sum is σ = 3213894827520. Its totient is φ = 226294548480.

The previous prime is 1030221113083. The next prime is 1030221113137. The reversal of 1030221113130 is 313111220301.

1030221113130 is a `hidden beast` number, since 10 + 302 + 211 + 13 + 130 = 666.

It is a super-2 number, since 2×10302211131302 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (1030221113137) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 34982772 + ... + 35012208.

It is an arithmetic number, because the mean of its divisors is an integer number (8369517780).

Almost surely, 21030221113130 is an apocalyptic number.

1030221113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1030221113130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1606947413760).

1030221113130 is an abundant number, since it is smaller than the sum of its proper divisors (2183673714390).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1030221113130 is a wasteful number, since it uses less digits than its factorization.

1030221113130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29566 (or 29563 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1030221113130 its reverse (313111220301), we get a palindrome (1343332333431).

The spelling of 1030221113130 in words is "one trillion, thirty billion, two hundred twenty-one million, one hundred thirteen thousand, one hundred thirty".