1030255117 has 4 divisors (see below), whose sum is σ = 1030361920. Its totient is φ = 1030148316.

The previous prime is 1030255111. The next prime is 1030255129. The reversal of 1030255117 is 7115520301.

1030255117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1030255117 - 2²³ = 1021866509 is a prime.

It is a super-2 number, since 2×1030255117² = 2122851212209367378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1030255091 and 1030255100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1030255111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37317 + ... + 58762.

It is an arithmetic number, because the mean of its divisors is an integer number (257590480).

Almost surely, 2^1030255117 is an apocalyptic number.

It is an amenable number.

1030255117 is a deficient number, since it is larger than the sum of its proper divisors (106803).

1030255117 is an equidigital number, since it uses as much as digits as its factorization.

1030255117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106802.

The product of its (nonzero) digits is 1050, while the sum is 25.

The square root of 1030255117 is about 32097.5874015478. The cubic root of 1030255117 is about 1009.9850068029.

Adding to 1030255117 its reverse (7115520301), we get a palindrome (8145775418).

The spelling of 1030255117 in words is "one billion, thirty million, two hundred fifty-five thousand, one hundred seventeen".