Base | Representation |
---|---|
bin | 10111011011010010011101… |
… | …001001100101101101001111 |
3 | 111111210121020121000122001112 |
4 | 113123102131021211231033 |
5 | 102001022034340024403 |
6 | 1003043245534202235 |
7 | 30462460115342600 |
oct | 2733223511455517 |
9 | 444717217018045 |
10 | 103030312033103 |
11 | 2a912a01169a84 |
12 | b67bb6b05337b |
13 | 456494188cac0 |
14 | 1b6299d779da7 |
15 | bda0c52269d8 |
hex | 5db49d265b4f |
103030312033103 has 24 divisors (see below), whose sum is σ = 129075629937408. Its totient is φ = 81515526797376.
The previous prime is 103030312033087. The next prime is 103030312033123. The reversal of 103030312033103 is 301330213030301.
It is not a de Polignac number, because 103030312033103 - 24 = 103030312033087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103030312033123) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14690450 + ... + 20539472.
It is an arithmetic number, because the mean of its divisors is an integer number (5378151247392).
Almost surely, 2103030312033103 is an apocalyptic number.
103030312033103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
103030312033103 is a deficient number, since it is larger than the sum of its proper divisors (26045317904305).
103030312033103 is a wasteful number, since it uses less digits than its factorization.
103030312033103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5876703 (or 5876696 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 103030312033103 its reverse (301330213030301), we get a palindrome (404360525063404).
The spelling of 103030312033103 in words is "one hundred three trillion, thirty billion, three hundred twelve million, thirty-three thousand, one hundred three".
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