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103030340311433 is a prime number
BaseRepresentation
bin10111011011010010011110…
…110101011101100110001001
3111111210121022120020022122002
4113123102132311131212021
5102001022114104431213
61003043252424240345
730462460610610653
oct2733223665354611
9444717276208562
10103030340311433
112a912a161239a7
12b67bb786100b5
1345649476b1242
141b629a341b6d3
15bda0c7960658
hex5db49ed5d989

103030340311433 has 2 divisors, whose sum is σ = 103030340311434. Its totient is φ = 103030340311432.

The previous prime is 103030340311411. The next prime is 103030340311553. The reversal of 103030340311433 is 334113043030301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97820862736249 + 5209477575184 = 9890443^2 + 2282428^2 .

It is a cyclic number.

It is not a de Polignac number, because 103030340311433 - 26 = 103030340311369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103030340311396 and 103030340311405.

It is not a weakly prime, because it can be changed into another prime (103030340301433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51515170155716 + 51515170155717.

It is an arithmetic number, because the mean of its divisors is an integer number (51515170155717).

Almost surely, 2103030340311433 is an apocalyptic number.

It is an amenable number.

103030340311433 is a deficient number, since it is larger than the sum of its proper divisors (1).

103030340311433 is an equidigital number, since it uses as much as digits as its factorization.

103030340311433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 103030340311433 its reverse (334113043030301), we get a palindrome (437143383341734).

The spelling of 103030340311433 in words is "one hundred three trillion, thirty billion, three hundred forty million, three hundred eleven thousand, four hundred thirty-three".