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10303121412307 is a prime number
BaseRepresentation
bin1001010111101110000111…
…1001000101000011010011
31100110222011020122110021201
42111323201321011003103
52322301243040143212
633525104424532031
72112242645005243
oct225734171050323
940428136573251
1010303121412307
113312590487609
1211a4992621017
1359977086b359
14278960a3db23
1512d01b679b57
hex95ee1e450d3

10303121412307 has 2 divisors, whose sum is σ = 10303121412308. Its totient is φ = 10303121412306.

The previous prime is 10303121412253. The next prime is 10303121412313. The reversal of 10303121412307 is 70321412130301.

10303121412307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (70321412130301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10303121412307 - 215 = 10303121379539 is a prime.

It is not a weakly prime, because it can be changed into another prime (10303121412007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5151560706153 + 5151560706154.

It is an arithmetic number, because the mean of its divisors is an integer number (5151560706154).

Almost surely, 210303121412307 is an apocalyptic number.

10303121412307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10303121412307 is an equidigital number, since it uses as much as digits as its factorization.

10303121412307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 10303121412307 its reverse (70321412130301), we get a palindrome (80624533542608).

The spelling of 10303121412307 in words is "ten trillion, three hundred three billion, one hundred twenty-one million, four hundred twelve thousand, three hundred seven".