Base | Representation |
---|---|
bin | 11101111111000110110… |
… | …01001011101000001011 |
3 | 10122111102020012101120201 |
4 | 32333203121023220023 |
5 | 113340034411304003 |
6 | 2105152514233031 |
7 | 134303045211613 |
oct | 16774331135013 |
9 | 3574366171521 |
10 | 1030312213003 |
11 | 367a534251a7 |
12 | 147821585777 |
13 | 76209246658 |
14 | 37c20123a43 |
15 | 1bc029b2b1d |
hex | efe364ba0b |
1030312213003 has 2 divisors, whose sum is σ = 1030312213004. Its totient is φ = 1030312213002.
The previous prime is 1030312212973. The next prime is 1030312213027. The reversal of 1030312213003 is 3003122130301.
It is a strong prime.
It is an emirp because it is prime and its reverse (3003122130301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1030312213003 - 29 = 1030312212491 is a prime.
It is not a weakly prime, because it can be changed into another prime (1030312213033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515156106501 + 515156106502.
It is an arithmetic number, because the mean of its divisors is an integer number (515156106502).
Almost surely, 21030312213003 is an apocalyptic number.
1030312213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030312213003 is an equidigital number, since it uses as much as digits as its factorization.
1030312213003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1030312213003 its reverse (3003122130301), we get a palindrome (4033434343304).
The spelling of 1030312213003 in words is "one trillion, thirty billion, three hundred twelve million, two hundred thirteen thousand, three".
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