Base | Representation |
---|---|
bin | 10111011011010011010011… |
… | …011100101001111111011011 |
3 | 111111210200121002011121011011 |
4 | 113123103103130221333123 |
5 | 102001030421042013201 |
6 | 1003043520155314351 |
7 | 30462521516422042 |
oct | 2733232334517733 |
9 | 444720532147134 |
10 | 103031223001051 |
11 | 2a913329402754 |
12 | b68018414b9b7 |
13 | 4564a585267a7 |
14 | 1b62a4874d559 |
15 | bda12a1bd151 |
hex | 5db4d3729fdb |
103031223001051 has 2 divisors, whose sum is σ = 103031223001052. Its totient is φ = 103031223001050.
The previous prime is 103031223001013. The next prime is 103031223001081. The reversal of 103031223001051 is 150100322130301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103031223001051 - 29 = 103031223000539 is a prime.
It is not a weakly prime, because it can be changed into another prime (103031223001081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51515611500525 + 51515611500526.
It is an arithmetic number, because the mean of its divisors is an integer number (51515611500526).
Almost surely, 2103031223001051 is an apocalyptic number.
103031223001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
103031223001051 is an equidigital number, since it uses as much as digits as its factorization.
103031223001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 103031223001051 its reverse (150100322130301), we get a palindrome (253131545131352).
The spelling of 103031223001051 in words is "one hundred three trillion, thirty-one billion, two hundred twenty-three million, one thousand, fifty-one".
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