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1030313410207 = 2710938006323
BaseRepresentation
bin11101111111000110111…
…01101111111010011111
310122111102022110012211121
432333203131233322133
5113340040213111312
62105153000031411
7134303061326164
oct16774335577237
93574368405747
101030313410207
11367a54072724
12147821a62567
1376209575563
1437c2035606b
151bc02b4c707
hexefe376fe9f

1030313410207 has 4 divisors (see below), whose sum is σ = 1030351443640. Its totient is φ = 1030275376776.

The previous prime is 1030313410177. The next prime is 1030313410249. The reversal of 1030313410207 is 7020143130301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1030313410207 - 239 = 480557596319 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1030313417207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18976053 + ... + 19030270.

It is an arithmetic number, because the mean of its divisors is an integer number (257587860910).

Almost surely, 21030313410207 is an apocalyptic number.

1030313410207 is a deficient number, since it is larger than the sum of its proper divisors (38033433).

1030313410207 is an equidigital number, since it uses as much as digits as its factorization.

1030313410207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38033432.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 1030313410207 its reverse (7020143130301), we get a palindrome (8050456540508).

The spelling of 1030313410207 in words is "one trillion, thirty billion, three hundred thirteen million, four hundred ten thousand, two hundred seven".

Divisors: 1 27109 38006323 1030313410207