Base | Representation |
---|---|
bin | 101111111110100101… |
… | …1110000110110011011 |
3 | 100211221110211020020122 |
4 | 1133331023300312123 |
5 | 3142002140422011 |
6 | 115155432343455 |
7 | 10305141161552 |
oct | 1377513606633 |
9 | 324843736218 |
10 | 103031967131 |
11 | 3a77194a965 |
12 | 17b75244b8b |
13 | 993ca07432 |
14 | 4db59c8d99 |
15 | 2a304e53db |
hex | 17fd2f0d9b |
103031967131 has 2 divisors, whose sum is σ = 103031967132. Its totient is φ = 103031967130.
The previous prime is 103031967113. The next prime is 103031967139. The reversal of 103031967131 is 131769130301.
Together with previous prime (103031967113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (131769130301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103031967131 - 26 = 103031967067 is a prime.
It is a super-2 number, since 2×1030319671312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103031967091 and 103031967100.
It is not a weakly prime, because it can be changed into another prime (103031967139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51515983565 + 51515983566.
It is an arithmetic number, because the mean of its divisors is an integer number (51515983566).
Almost surely, 2103031967131 is an apocalyptic number.
103031967131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103031967131 is an equidigital number, since it uses as much as digits as its factorization.
103031967131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10206, while the sum is 35.
The spelling of 103031967131 in words is "one hundred three billion, thirty-one million, nine hundred sixty-seven thousand, one hundred thirty-one".
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