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103031967131 is a prime number
BaseRepresentation
bin101111111110100101…
…1110000110110011011
3100211221110211020020122
41133331023300312123
53142002140422011
6115155432343455
710305141161552
oct1377513606633
9324843736218
10103031967131
113a77194a965
1217b75244b8b
13993ca07432
144db59c8d99
152a304e53db
hex17fd2f0d9b

103031967131 has 2 divisors, whose sum is σ = 103031967132. Its totient is φ = 103031967130.

The previous prime is 103031967113. The next prime is 103031967139. The reversal of 103031967131 is 131769130301.

Together with previous prime (103031967113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (131769130301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103031967131 - 26 = 103031967067 is a prime.

It is a super-2 number, since 2×1030319671312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103031967091 and 103031967100.

It is not a weakly prime, because it can be changed into another prime (103031967139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51515983565 + 51515983566.

It is an arithmetic number, because the mean of its divisors is an integer number (51515983566).

Almost surely, 2103031967131 is an apocalyptic number.

103031967131 is a deficient number, since it is larger than the sum of its proper divisors (1).

103031967131 is an equidigital number, since it uses as much as digits as its factorization.

103031967131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10206, while the sum is 35.

The spelling of 103031967131 in words is "one hundred three billion, thirty-one million, nine hundred sixty-seven thousand, one hundred thirty-one".