10303442130031 has 4 divisors (see below), whose sum is σ = 10318751851552. Its totient is φ = 10288132408512.

The previous prime is 10303442130029. The next prime is 10303442130083. The reversal of 10303442130031 is 13003124430301.

10303442130031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10303442130031 - 2¹ = 10303442130029 is a prime.

It is a super-2 number, since 2×10303442130031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10303442129978 and 10303442130005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10303442130011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7654859751 + ... + 7654861096.

It is an arithmetic number, because the mean of its divisors is an integer number (2579687962888).

Almost surely, 2^{10303442130031} is an apocalyptic number.

10303442130031 is a deficient number, since it is larger than the sum of its proper divisors (15309721521).

10303442130031 is an equidigital number, since it uses as much as digits as its factorization.

10303442130031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15309721520.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10303442130031 its reverse (13003124430301), we get a palindrome (23306566560332).

The spelling of 10303442130031 in words is "ten trillion, three hundred three billion, four hundred forty-two million, one hundred thirty thousand, thirty-one".