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10304456130193 is a prime number
BaseRepresentation
bin1001010111110011000101…
…1100100111111010010001
31100111002121021011011000111
42111330301130213322101
52322312011232131233
633525445104321321
72112321012634111
oct225746134477221
940432537134014
1010304456130193
113313105937945
1211a50a5613241
13599924240854
14278a49ddb041
1512d098926acd
hex95f31727e91

10304456130193 has 2 divisors, whose sum is σ = 10304456130194. Its totient is φ = 10304456130192.

The previous prime is 10304456130187. The next prime is 10304456130211. The reversal of 10304456130193 is 39103165440301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10073818949184 + 230637181009 = 3173928^2 + 480247^2 .

It is an emirp because it is prime and its reverse (39103165440301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10304456130193 is a prime.

It is a super-2 number, since 2×103044561301932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10304457130193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5152228065096 + 5152228065097.

It is an arithmetic number, because the mean of its divisors is an integer number (5152228065097).

Almost surely, 210304456130193 is an apocalyptic number.

It is an amenable number.

10304456130193 is a deficient number, since it is larger than the sum of its proper divisors (1).

10304456130193 is an equidigital number, since it uses as much as digits as its factorization.

10304456130193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 40.

The spelling of 10304456130193 in words is "ten trillion, three hundred four billion, four hundred fifty-six million, one hundred thirty thousand, one hundred ninety-three".