Base | Representation |
---|---|
bin | 11101111111011101101… |
… | …01101101100010000001 |
3 | 10122111220121112102212011 |
4 | 32333232311231202001 |
5 | 113340433041210111 |
6 | 2105223534132521 |
7 | 134310566345044 |
oct | 16775665554201 |
9 | 3574817472764 |
10 | 1030504241281 |
11 | 368041862959 |
12 | 147875951141 |
13 | 76239c6c358 |
14 | 37c3b82cc5b |
15 | 1bc14795021 |
hex | efeed6d881 |
1030504241281 has 2 divisors, whose sum is σ = 1030504241282. Its totient is φ = 1030504241280.
The previous prime is 1030504241227. The next prime is 1030504241293. The reversal of 1030504241281 is 1821424050301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 603822243600 + 426681997681 = 777060^2 + 653209^2 .
It is a cyclic number.
It is not a de Polignac number, because 1030504241281 - 221 = 1030502144129 is a prime.
It is a super-2 number, since 2×10305042412812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1030504241201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515252120640 + 515252120641.
It is an arithmetic number, because the mean of its divisors is an integer number (515252120641).
Almost surely, 21030504241281 is an apocalyptic number.
It is an amenable number.
1030504241281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030504241281 is an equidigital number, since it uses as much as digits as its factorization.
1030504241281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 1030504241281 its reverse (1821424050301), we get a palindrome (2851928291582).
The spelling of 1030504241281 in words is "one trillion, thirty billion, five hundred four million, two hundred forty-one thousand, two hundred eighty-one".
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