Base | Representation |
---|---|
bin | 1001010111111011001100… |
… | …0101010000100010110011 |
3 | 1100111022012211122011211222 |
4 | 2111332303011100202303 |
5 | 2322330440021341001 |
6 | 33530445000255255 |
7 | 2112425632246364 |
oct | 225766305204263 |
9 | 40438184564758 |
10 | 10306631043251 |
11 | 3314021592254 |
12 | 11a55b1a7152b |
13 | 599bac9ca55a |
14 | 278bb4bc7b6b |
15 | 12d17483a61b |
hex | 95fb31508b3 |
10306631043251 has 2 divisors, whose sum is σ = 10306631043252. Its totient is φ = 10306631043250.
The previous prime is 10306631043229. The next prime is 10306631043263. The reversal of 10306631043251 is 15234013660301.
10306631043251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (15234013660301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10306631043251 is a prime.
It is not a weakly prime, because it can be changed into another prime (10306631043551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5153315521625 + 5153315521626.
It is an arithmetic number, because the mean of its divisors is an integer number (5153315521626).
Almost surely, 210306631043251 is an apocalyptic number.
10306631043251 is a deficient number, since it is larger than the sum of its proper divisors (1).
10306631043251 is an equidigital number, since it uses as much as digits as its factorization.
10306631043251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 10306631043251 in words is "ten trillion, three hundred six billion, six hundred thirty-one million, forty-three thousand, two hundred fifty-one".
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