Base | Representation |
---|---|
bin | 1001011000000111110010… |
… | …1110010111110010001011 |
3 | 1100111121221121100021122022 |
4 | 2112001330232113302023 |
5 | 2322404402043304402 |
6 | 33532204405515055 |
7 | 2112605521252265 |
oct | 226017456276213 |
9 | 40447847307568 |
10 | 10310014041227 |
11 | 33154a816574a |
12 | 11a6196a12a8b |
13 | 59a2cb84c6c4 |
14 | 27901620ab35 |
15 | 12d2c18352a2 |
hex | 9607cb97c8b |
10310014041227 has 2 divisors, whose sum is σ = 10310014041228. Its totient is φ = 10310014041226.
The previous prime is 10310014041181. The next prime is 10310014041277. The reversal of 10310014041227 is 72214041001301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10310014041227 - 28 = 10310014040971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10310014041196 and 10310014041205.
It is not a weakly prime, because it can be changed into another prime (10310014041277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155007020613 + 5155007020614.
It is an arithmetic number, because the mean of its divisors is an integer number (5155007020614).
Almost surely, 210310014041227 is an apocalyptic number.
10310014041227 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310014041227 is an equidigital number, since it uses as much as digits as its factorization.
10310014041227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 10310014041227 its reverse (72214041001301), we get a palindrome (82524055042528).
The spelling of 10310014041227 in words is "ten trillion, three hundred ten billion, fourteen million, forty-one thousand, two hundred twenty-seven".
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