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1031003301113 is a prime number
BaseRepresentation
bin11110000000011001001…
…01011110010011111001
310122120012101121022020122
433000030211132103321
5113342443321113423
62105345242503025
7134326136315012
oct17001445362371
93576171538218
101031003301113
113682785379a5
12147994b04a75
13762b9485526
1437c87c1c009
151bc434c48c8
hexf00c95e4f9

1031003301113 has 2 divisors, whose sum is σ = 1031003301114. Its totient is φ = 1031003301112.

The previous prime is 1031003301047. The next prime is 1031003301143. The reversal of 1031003301113 is 3111033001301.

1031003301113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 606222631609 + 424780669504 = 778603^2 + 651752^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031003301113 - 218 = 1031003038969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1031003301091 and 1031003301100.

It is not a weakly prime, because it can be changed into another prime (1031003301143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515501650556 + 515501650557.

It is an arithmetic number, because the mean of its divisors is an integer number (515501650557).

Almost surely, 21031003301113 is an apocalyptic number.

It is an amenable number.

1031003301113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031003301113 is an equidigital number, since it uses as much as digits as its factorization.

1031003301113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1031003301113 its reverse (3111033001301), we get a palindrome (4142036302414).

The spelling of 1031003301113 in words is "one trillion, thirty-one billion, three million, three hundred one thousand, one hundred thirteen".