103100400314 has 4 divisors (see below), whose sum is σ = 154650600474. Its totient is φ = 51550200156.

The previous prime is 103100400313. The next prime is 103100400329. The reversal of 103100400314 is 413004001301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 82860501025 + 20239899289 = 287855^2 + 142267^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 103100400292 and 103100400301.

It is not an unprimeable number, because it can be changed into a prime (103100400313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25775100077 + ... + 25775100080.

Almost surely, 2^103100400314 is an apocalyptic number.

103100400314 is a deficient number, since it is larger than the sum of its proper divisors (51550200160).

103100400314 is an equidigital number, since it uses as much as digits as its factorization.

103100400314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51550200159.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 103100400314 its reverse (413004001301), we get a palindrome (516104401615).

The spelling of 103100400314 in words is "one hundred three billion, one hundred million, four hundred thousand, three hundred fourteen".