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103100542053 = 334366847351
BaseRepresentation
bin110000000000101000…
…1010110110001100101
3100212010020212012100120
41200001101112301211
53142122214321203
6115210322232153
710306633101465
oct1400121266145
9325106765316
10103100542053
113a7a7628253
1217b941b5659
139950c97402
144dc0b59ba5
152a3653db53
hex1801456c65

103100542053 has 4 divisors (see below), whose sum is σ = 137467389408. Its totient is φ = 68733694700.

The previous prime is 103100542043. The next prime is 103100542057. The reversal of 103100542053 is 350245001301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103100542053 - 25 = 103100542021 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103100542057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17183423673 + ... + 17183423678.

It is an arithmetic number, because the mean of its divisors is an integer number (34366847352).

Almost surely, 2103100542053 is an apocalyptic number.

It is an amenable number.

103100542053 is a deficient number, since it is larger than the sum of its proper divisors (34366847355).

103100542053 is an equidigital number, since it uses as much as digits as its factorization.

103100542053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34366847354.

The product of its (nonzero) digits is 1800, while the sum is 24.

Adding to 103100542053 its reverse (350245001301), we get a palindrome (453345543354).

The spelling of 103100542053 in words is "one hundred three billion, one hundred million, five hundred forty-two thousand, fifty-three".

Divisors: 1 3 34366847351 103100542053