Base | Representation |
---|---|
bin | 11110000000011010001… |
… | …10110001111000010011 |
3 | 10122120020000000212210112 |
4 | 33000031012301320103 |
5 | 113343003040011034 |
6 | 2105350153551535 |
7 | 134326303450364 |
oct | 17001506617023 |
9 | 3576200025715 |
10 | 1031012032019 |
11 | 368282460622 |
12 | 147997a155ab |
13 | 762bb221548 |
14 | 37c89051b6b |
15 | 1bc4414b7ce |
hex | f00d1b1e13 |
1031012032019 has 2 divisors, whose sum is σ = 1031012032020. Its totient is φ = 1031012032018.
The previous prime is 1031012031953. The next prime is 1031012032027. The reversal of 1031012032019 is 9102302101301.
It is a strong prime.
It is an emirp because it is prime and its reverse (9102302101301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1031012032019 - 212 = 1031012027923 is a prime.
It is a super-2 number, since 2×10310120320192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1031012031985 and 1031012032003.
It is not a weakly prime, because it can be changed into another prime (1031012032069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515506016009 + 515506016010.
It is an arithmetic number, because the mean of its divisors is an integer number (515506016010).
Almost surely, 21031012032019 is an apocalyptic number.
1031012032019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031012032019 is an equidigital number, since it uses as much as digits as its factorization.
1031012032019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 1031012032019 in words is "one trillion, thirty-one billion, twelve million, thirty-two thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •